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Yeh, thats what i got. Haha, that would be awesome if you did. Nice work realising m = v/l to cancel them out.

So did i, its just easier to put everything in degrees. Easier to read. Hm, depends how much knowledge you showed about the theory related to the question. If you just made a stupid mistake, maybe 1.

Yeh there were some tricky parts, finished 5-10 mins early with everything done. Though i know now I made a couple silly mistakes Didnt put the minutes into time. Make a silly error in calculating the height, all theory right though. And possibly the first question wrong.. i dont remember...

let theta = y (for simplicity) dy/dt = (vl)/(l^2 + x^2) = m/4 = v/4l (vl)/(l^2 + x^2) = v/4l simplify to 3l^2 = x^2 From the diagram x = ltany simplifes to tany = + or - sqrt(3) It is in the range -90 < y < 90 So its plus or minus 60

Re: What did you think? No, that is what I did and you get exactly the same answer as using u^2 = 2x-1. Though your answer is wrong, should be pi/6 I think. Though you should still get full marks, just dropped a two somewhere.

Re: What did you think? It was different, lots of 3u, and very little mechanics. I put b as the maximum velocity, so yeh probably speed of the current aswell. Delta was not a constant. I realised after i walked out that you need to sub in delta = pi/2n or something like that, I think.