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Oi just remember that:Tommy_Lamp said:What I have memorised:
4Fe(s) + SO42- + 5H2O(l) ----> FeS(s) + 3Fe(OH)2(s) + H2O(l) + 2OH-(aq)
Black iron (II) sulfide forms on the steel along with iron (II) hydroxide (which in absence of O2 does not form iron (III) as in normal corrosion).