cal. (1 Viewer)

[spikestar]

Hi, can some 1 plz tell me how do i find the anti-diff of y=Ln(x)

 

[housemouse]

Integration by parts??????

 

[spikestar]

yes, !

 

[STx]

well done...

 

[Mountain.Dew]

using integration by parts...

this will get u started...make v' = 1, u = lnx.

go from there

 

[hyparzero]

surely you can use the Machurin Series, much more practical and confuses the teacher?

 

[Slidey]

Um... I think you mean Mclaurin. And unless you plan to write up a detailed explanation for the other users of this forum, it'd be best to leave Mclaurin series out of this.

Risking marks in exams is entirely your onus.

 

[hyparzero]

whoops, i meant Maclaurin Series

Explanation
A Maclaurin series is a Taylor series expansion of f(x) about 0, also known as a power series.

It is primarly used to approximately integrate transcendal functions such as e^x2

f(x) = f(0) + f'(0)x + f''(0)x² /2! + f'''(0)x³ /3! + f⁽⁴⁾(0)x⁴ /4! + f⁽⁵⁾(0)x⁵ /5! + ............ and so on to infinity

 

[hyparzero]

Slight problem: the "MacLaurin series" of ln(x) doesn't exist - try deriving it.

instead of using fⁿ(0), use fⁿ(1)
and replace all xⁿ with (x-1)ⁿ

 

[Yip]

as u said before hyparzero, maclaurin series are about 0, not 1

 

[hyparzero]

as u said before hyparzero, maclaurin series are about 0, not 1

Taylor

 

[Roobs]

hmmm.....ill stick to parts, appease the board and then men upstairs, n then figure out nifty methods later......

the hsc is bad enough without trying to do things in a manner more complicated than required

 

[Rax]

hmmm.....ill stick to parts, appease the board and then men upstairs, n then figure out nifty methods later......

the hsc is bad enough without trying to do things in a manner more complicated than required

Amen to that. All this serious stuff is messin with me already.

On a Side Note, Hello Roobs. I belive I saw you at the Maths Extension II day by Mark Arnold in Lismore.
And thats about it.

GG