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  1. M

    mechanics plz help.

    making t the subject before replacing it with infinity is definately easier, didnt think of that when i did it
  2. M

    mechanics plz help.

    it is possible to work out the terminal velocity using a <i>t → ∞</i> method but it uses <i>l'hopitals</i> rule [EDIT: l'hopitals rule not needed] this is attached to the message, however the intended way is clearly the <i>a → 0</i> method posted by <i>Ogden_Nash</i> EDIT: Do NOT use...
  3. M

    Hard Projectile Q

    thats an interesting question my solutions attached
  4. M

    phys1131 poll

    how hard is phys1231 compared to phys1131?
  5. M

    phys1131 poll

    just wondering how people found the phys1131 course
  6. M

    Trig problems...

    sorry <i>who_loves_maths</i>, i was responding to what <i>sladehk</i> said before, not what you said just wanted to make clear that these questions had nothing to do with finding exact values, showing or proving anything
  7. M

    Trig problems...

    cos 46 = <sup>√2</sup>/<sub>360</sub> * (180 - π) was obtained using an approximation technique and is therefore not the exact value <sup>√2</sup>/<sub>360</sub> * (180 - π) = 0.694765439691663173714689137134 (approx) cos 46 = 0.694658370458997286656406299422 (approx) as you can see the...
  8. M

    Trig problems...

    i guess the only point would be to express sin 61 in a form that gives a clearer idea of its value. e.g. on observation u could say √3 = about 1.7, pi about 3.1 which gives an idea of the value of 1/360 * (180√3 + π)
  9. M

    Trig problems...

    the course name for math1141 is higher maths 1A, its basically math1131 (maths 1A) in greater depth. see: http://www.handbook.unsw.edu.au/undergraduate/courses/2005/MATH1141.html
  10. M

    Trig problems...

    its an approximation technique taught in math1141 at unsw: http://www2.maths.unsw.edu.au/ForStudents/courses/math3241/calculus/hcalchap3_PorTcd2.pdf look at page 12
  11. M

    Trig problems...

    answering the first question you can get a close approximation to sin 61 in a similar way 61 degrees = 61π/180 rads sin 61π/180 = sin 60π/180 + cos 60π/180 * π/180 (approximately) √3/2 + 1/2 * π/180 1/360 * (180√3 + π) = 0.874752050044410294648341624597 (approx) sin 61 =...
  12. M

    Trig problems...

    based on the answer to question 2 you're not looking for an exact value of cos 46, just a way to get a very close approximation let y = cos x <sup>dy</sup>/<sub>dx</sub> = -sin x because <sup>Δy</sup>/<sub>Δx</sub> = -sin x Δy = -sin x * Δx so y+Δy can be approximated by cos x -...
  13. M

    online graphing calculator

    slide rule recommended graphmatica in a previous thread: http://www8.pair.com/ksoft/grmat20n.zip
  14. M

    S.H.M - Netwon's Law of Cooling - Inverse Functions

    because the minimum value is 9 and the maximum 12 and the object moves with SHM, the object is oscillating about the line x=10.5 because 10.5 is in the middle of 9 and 12 the amplitude is 1.5 because 9 = 10.5 - 1.5 and 12 = 10.5 + 1.5 (1/2 the difference between the max and min values)...
  15. M

    Halving The Interval

    1. put the equation into the form f(x) = 0 2. obtain 2 estimates of the root x<sub>1</sub> and x<sub>2</sub> such that f(x<sub>1</sub>) < 0 and f(x<sub>2</sub>) > 0 (therefore a root exists between x<sub>1</sub> and x<sub>2</sub>) 3. find x<sub>3</sub> = <sup>1</sup>/<sub>2</sub> *...
  16. M

    S.H.M - Netwon's Law of Cooling - Inverse Functions

    sorry, forgot to answer the second SHM question, answer attached
  17. M

    S.H.M - Netwon's Law of Cooling - Inverse Functions

    solution to the first one is attached below
  18. M

    O! (that's zero factorial)

    you can integrate cos<sup>2</sup>x and sin<sup>2</sup>x by using complex numbers (example of sin<sup>2</sup>x attached) <sup>n</sup>P<sub>n</sub> = n! <sup>n</sup>P<sub>r</sub> = <sup>n!</sup>/<sub>(n-r)!</sub> therefore <sup>n</sup>P<sub>n</sub> = <sup>n!</sup>/<sub>0!</sub> = n! n...
  19. M

    A.M. >= G.M.

    a generic AM >= GM proof was put in the end of session exam for math1141 (attached)
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