hey guys i need urgent help in physics. i dont care if its over the net or we meet somewhere in the penrith blacktown area.
Any one with experience would be heaps of help
thanks
i think i just worked it out, is my reasoning correct
y=mx
y'=3e^3x
m =3e^3x
e^3x=3e^3x
x=1/3
m=3e^3(1/3)
m=3e^1
m=3e
im not sure if that is the right working but it gives the right answer
This is a simple question but i think i am missing something and can not get the answer it is
the line y=mx is a tangent to the curve y=e^3x find m
the answer is 3e
thanks in advance
has any one got a working link to the text book answers. I no there on the net cause i was using them, but now the link does not work and i cant find them through google. Help
Hi just wondering if any one uses the Cambridge text book and if it is as good as the others.
it would also be extremly helpful if any one hand any notes on the information sytems and database topic based on this textbook
Thats like my school. We do the year 11 and year 12 mathematics course in year 11 so i did the HSC last year and in year 12 we do the Ext maths. Its faced paced but there is no chance of getting bored and we have the option of redoing the HSC if we wont
u could use a program called robo demo 5. i dont think you can download it but my school gave it to me. it makes flash movies that u could put on the webpage. i used it for my assignment and got a pritty good mark.
there is also a program that you could download called jing project. it is a bit...
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thanks
i tried to do it like this
asin@ +bcos@ = rsin(@+&) where r= Square root of (a squared + b squared) And tan & = b/a
a= 4
b=1
r = Square root 17
tan & = 1/4
& = 14deg12min
4sin@ - cos@ = square root 17sin(@ + 14deg12min)
root17sin(@+14deg12min) = -3
base angle = 46deg41min
@+...
I am having real problems solving trig equations using asin@ + bcos@ = r (@ + &)
sorry for the bad symbols & is alpha
i keep geting every question wrong i think it is something small i am doing could someone please help with this question
4sin@ - cos@ + 3 = 0
the answers are 240 degrees...