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We'll see how you go this year won't we?

Agreed. 10 chars

is this using the raw score or the percentile?

by international standards you can, however, in Australia some teachers insist that "they haven't seen it before" and so you get marked down. BUT it is accepted in other countries. in fact students use that in the HSC assessments, and have to argue their way to their teachers and show them...

lim x-->0 (1-cosx)/(x^2) * (1+cosx)/(1+cosx) = lim x-->0 (sinx)^2 // [(x^2)(1+cosx)] split this up into lim x-->0 (sinx)^2//(x^2) * [1/(1+cosx)] hence lim x-->0 sinx/x * sinx/x * [1/(1+cosx)] sinx/x =1, sub x=0 into [1/(1+cosx)] and u get 0.5 therefore 1 * 1 * 0.5 = 0.5

there is an easier way to that question. multiply (1-cosx)/(x^2) by (1+cosx)/(1+cosx)

physical journey--peter skrzynecki emma and clueless speeches antony and cleopatra