This is probably a bit late for most people but this page has all the 4u hsc papers going back to 1967 (as well as catholic back to 1982 and plenty of trials) so that should suffice for anyone who has run out of papers to do.
http://au.geocities.com/ext2papers/
I'm quite sure its impossible to find an exact solution to that equation with elementary functions (that is exponential, logarithm, trig & inverse trig, algebraic.
Happy Feet's question is quite nice
use the cosine rule and the area of the triangle with sine thingamy.
We get:
RTP: a^2 + b^2 + a^2 + b^2 - 2abcosC >= 2*rt(3)*absinC
RTP: a^2 + b^2 >= abcosC + rt(3)*absinC
RTP: a^2 + b^2 >= ab(cosC + rt(3)*sinC)
but we know by AM-GM a^2 +...
Undalay, I don't want to sound elitist anything (lets face high isn't all that good at sport either compared to the GPS) but I don't think the GPS would be looking for another school to join, let alone a public school. Most of the schools already look down on High because we're public and the...
I never knew I had such a reputation. I am honoured (sincerely - I don't want to come off as too much of an arrogant prick). And I accept your apology.
I would have to agree with simonloo's suggestion that Ruse is a better school than Fort Street in most respects. Academically I would...
Way to destroy the lovely argument we had going Stone Monkey, yet ironically in your chastising of me for being "snarky", "wanton" and "offensive", you seem to have committed the same sins.
Now to answer your two questions of me (I will take the bait)
- I attend Sydney Boys High School...
Oh excellent. Just clarifying the bold bit: 5 actually has degree 0 (just like how the constant polynomial has degree 0) Possibly one way to think about this is that 5a^3/b could be written a^3/b + a^3/b + a^3/b + a^3/b + a^3/b. and now its clear that each term has degree 2.
I don't have...
If you can't work out which school she goes to when all it takes is one click then obviously you're not going to have much chance when it comes to the Physics Olympiad.
Anyway - she's achieved far more than you ever have (and most likely more than you will) so you really shouldn't be talking...
Don't worry about it all kagrawal. These sort of questions require vry different sort of thinking to those that you would get in 3u. And the mathematics required to solve this problem (modular arithmetic) is completely unneccessary for the 3u (or any nsw hsc) syllabus.
I don't think theres...
Umm - this is quite tricky to understand and even harder to explain over a forum but i think that if i just gave you the factorisation that would be quite useless so i will try to continue explaining.
lets start of with something easier first to explain the factor theorem.
let f(n) = n^2 -...
I don't see that as working because this is only really valid when the exponents are a specific set of numbers. These questions are very different to the 3u questions where you asked to prove the divisibility by induction and they require far stronger techniques.
And kagrawal - where did u...
This is quite tricky - its especially hard to show a motivation for finding the solution but heres some ideas on how i got the factorisation.
Notice firstly that c is special variable in a sense that the expression is symmetric in a and b (ie you can swap them around and get exactly the same...
I'm guessing that this is from the Polya Enrichment Series? (sounds like one of those questions)
So with this question you have to use modular arithmetic and also notice the prime factorisation of 174 = 2*3*29
so basically the problem reduces to three sub problems of proving the expression...
I hate to break it to you guys but it was hoax from those most reputable British Papers, the Metro and the Sun.
http://www.snopes.com/critters/lurkers/poodlesheep.asp for the real details. Quite disappointing how it got picked up by reputable news sources around the world (including our SMH...
sorry I'm a bit lazy. The basic idea is to get rid of the square roots because they impede calculations. So you put all the square roots on one side and the square it.
Now you should be left with only 1 square root. put it on its own side again and square again. Now there should be no...
Lovely questions ;). If you try putting either 2 or 3 into the Integrator (integrate.wolfram.com) you get a huge expression which is impossible to evaluate, but the using the substitution makes them so much nicer.