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usuc ravin. i cant believe u couldnt get part i. o m g

using the calculator to work out sin60 etc without the need for a triangle ---> plug sin60 into ur calc..=0.866025..... then square it = 0.75= 3/4 that means sin60= root3/2 etc...

How does energy occuring in quanta make energy being emitted in varying frequencies possible? even if light wasnt in quanta wouldnt it be emitted in a lot of frequencies?

ok nevermind i got it... wow this is a tough question i did it a geometric way, which was a bit less confusing

zeek, how did cis(0)+cos(@) become 2cos^2(@/2) ???

yeh but the thing is, the dip is the left hand side bit, which is the region with lower wavelength, therefore higher frequency, giving them more energy...

99.95 yeh right

ok this part in the syllabus is really gay in my opinion. firstly, how did explaining that light in is quanta fit the experimental results in the graphs? because if ur using E=hf, the smaller the frequency the larger the energy, which does not explain the left hand side "dip" in black body...

maybe it will help with the next part: Hence show that (1+z)^4= 16(cos theta/2)^4 x (cis2theta)

z=cos(theta)+isin(theta) express 1+z in mod/arg form

not really to me...

i got 87%...scaled nooooooooooooooooo they havent given me my raw yet, but its in the range of 55/75 to 60/75....which is crap! thats about 70%

yay finished my half yearlies! i thought i did ok in most pretty sure i got 100 in 3u maths and around 90s for chem/phy but i can only get 70-80 for 4u.... nnooooooooooooooooooooooooooo

really

88 ppl do standard english, and 86 do standard maths?

wonder wat holly valance has to do with it

cyl u still online?

joe ible? hey tango- who are you?

yeh

a) A+B+C= -1 b) A^2+B^2+C^2= (A+B+C)^2 -2(AB +BC+AC) = 1- 0 =1 c) sub roots into eqn: so A^3+A^2+2=0 similarly B^3+B^2+2=0 and C^3+C^2+2=0 now add all 3 eqns: A^3+B^3+C^3 +A^2+B^2+C^2+ 8=0 A^3+B^3+C^3+ 1+8=0 therefore A^3+B^3+C^3=-9 for d) do...