Another method.
(nc1)^2 + 2(nc2)^2... + n(ncn)^2
= n/2 [ (nc0)^2 + (nc1)^2 ...+(ncn)^2) ] (since nCk = nC(n-k))
= n/2 . (2n)!/(n!)^2 (an almost standard result)
= n(2n-1)c(n-1) after some basic algebra.
tutor01: you knew what I meant p
"Speer's work shows insight into the Nazi Regime."
In light of this statement, assess this statement.
(something retarded like that)
ARRGH
Speer shall bring me down :(
Nobody here believes no_arg's statement.
But let us suppose it was true, then none of us could ever use it anyway because it would the expression is both utterly useless and unusable without a proof.
I await the closure of this thread too.