At room temperature, there are atomic vibrations within the lattice which cause great amounts of collisions with the electron current, thus providing more resistance
At superconductors below the critical temp, there are no atomic vibrations thus no resistance
Say you are using an incadescent lightbulb to test the photoelectric effect with a data logger/photocell. As the light bulb heats up, would it emit more photons? why?
You should get a set of values of AAS readings for known ppm concentrations, plot them on a graph accurately. You should then be given a AAS value for your sample, find that value on the graph and you can see the ppm of it aswell
(*THIS IS ALL WRONG*)
From Double angle formulas, sin2x = 2cos²x-1
so 2cos²x-1=cosx
2cos²x-cosx-1=0
let y=cos x
2y²-y-1=0
(y-2)(y+1)=0
y=2,-1
cosx=2
cosx=-1
solve from there
Yeah you were
, for 1ppm standard solution concentration the AAS was 0.105, for 2ppm it was 0.195, for 3ppm it was 0.285, for 4ppm it was 0.375
so do you compare those values to yours?
Can anyone tell me how this is done?? For instance if you have 5mls of oil diluted to 50mls with a suitable solvent and you're testing for silver with AAS and get a reading of 0.230, how do you calculate the concentration of silver in ppm
btw this is from the NEAP CM&M paper
Yess, so two lights (blue and red) of the same intensity would produce the same current assuming the metal will liberate electrons to both these colours?
http://lectureonline.cl.msu.edu/~mmp/kap28/PhotoEffect/photo.htm
Why does this applet increase current with frequency then :confused: its...