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This whole scaling aligning etc. is too complicated, so don't worry, you'll get whatever you deserve to get :)

Yeah the ones that produce H2(g) and Br(aq)

Add Fe3+ and a green residue forms.

I got D, I wont explain it but you had to use the standard potentials table.

It said the smallest are detected first, hence hexanol is the correct answer.

Probably 90+

I thought the test was ok, harder than previous years but good. I agree though, alot of extended responses.

Stopped revising at 6pm, ate dinner, gonna have a good nights sleep.

Increased nutrients, abundance of life-forms, oxygen used up, life-forms die, form sludge on bottom of water, process repeats, eventually waterway disappears

You can see that they don't write on your paper by looking at the sample answers in the standards packages.

Yes, because you need to know which indicator to use in a titration. Phenolphthalien colour change occurs in the basic range Bromothymol Blue occurs in the neutral Methyl acidic The last 2 might be mixed up :p

"Outline the role of a chemist employed in a named industry or enterprise, identifying the branch of chemistry undertaken by the chemist and explaining a chemical principle that the chemist uses " :)

For part 2, it also easily collected from leaching and hydrothermal vents.

It's a flow chart, I've written one up and I think its on the resources page.

Yeah I can see what you mean, but trust me, all you need is a named branch. :)

SI units are kg and L?

q24a) You would do a titration. Titrate the vinegar with sodium hydroxide. This is weak acid + strong base hence equivalence point would be basic, hence Phenolphthlein indicator. q24b) Using your value of the acetic acid concentration in a), you just do a basic calculation. c1v1 = c2v2 v1 =...

Depends on what the volume of the solutions is given in, generally mL, but if both are mL's then it doesnt matter, same as if both are L. The ratio is the same.

i change the specific heat capacity of water to g, making it 4.18 even, good since water is generally in mL's also, not L

thanks yes its L because its mol L-1 :)