ashokkumar
Mr
5 travellers arrive at a town that has 3 hotels. Two of the travellers, Joanne and David, wish to stay in the same hotel. In how many ways can the 5 travellers occupy the hotels, if each hotel must be occupied by at least 1 person?
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lol?Thong wishes he had Fiona
(But yea an explanation of how to do the question would be helpful)
OrIt is given that 3 hotels must be occupied.
Since Joanne and David are always staying together they are to be counted as 1 unit. There are three other ppl left, so together there are 4units.
so in nPr, n=4 and r=3.
Then the number of possibilities is 4P3.
However, there are 4 units and 3 hotels, this means that 1 unit will be left out and must stay in another hotel that is occupied. For this 1 unit there are 3 possibilities, which are the hotels.
So the total possibilities are 4P3 x 3 = 72.
correct me if im wrong.