J jks22 Member Joined Jan 18, 2022 Messages 66 Gender Male HSC 2022 Jul 20, 2022 #2 lmao1010 said: View attachment 35949 thx Click to expand... I think that's x radians so multiply it by 180/pi to convert it to degrees So that's y = sin(180x/pi) thus y' = 180/pi x cos(180x/pi) and you can convert it back to radians
lmao1010 said: View attachment 35949 thx Click to expand... I think that's x radians so multiply it by 180/pi to convert it to degrees So that's y = sin(180x/pi) thus y' = 180/pi x cos(180x/pi) and you can convert it back to radians
C cossine Well-Known Member Joined Jul 24, 2020 Messages 627 Gender Male HSC 2017 Jul 20, 2022 #3 lmao1010 said: View attachment 35949 thx Click to expand... It is not exactly clear what are trying to ask. What ratio do you want the amplitude to be with respect to half the period. 1:180 or 1: i Presuming want the former than: y' = pi/180 * cos(x) This more complicated than if ratio is 1: i. As if you let pi radians = 180 degrees, you will end up with y' = cos(x). The proof of the theorem sin(x) d/dx = cos(x) is beyond the scope of advanced maths so just accept the theorem.
lmao1010 said: View attachment 35949 thx Click to expand... It is not exactly clear what are trying to ask. What ratio do you want the amplitude to be with respect to half the period. 1:180 or 1: i Presuming want the former than: y' = pi/180 * cos(x) This more complicated than if ratio is 1: i. As if you let pi radians = 180 degrees, you will end up with y' = cos(x). The proof of the theorem sin(x) d/dx = cos(x) is beyond the scope of advanced maths so just accept the theorem.
