hey, im a bit newb. help would be a appreciated Simplify the expression, in the pic
skepticality Member Joined Feb 2, 2005 Messages 31 Location Sydney Gender Male HSC 2006 Oct 23, 2005 #1 hey, im a bit newb. help would be a appreciated Simplify the expression, in the pic
I icycloud Guest Oct 23, 2005 #2 Let z = 5 + 12i, conj(z) = Z = 5-12i Expression becomes: [Sqrt(z) + Sqrt(Z)] / [Sqrt(z) - Sqrt(Z)] = [Sqrt(z) + Sqrt(Z)]^2 / [z - Z] = (z + Z + 2Sqrt(zZ)) / (z-Z) = (10 + 2Sqrt(169)) / (24i) = (10 + 26) / 24i = 36/(24i) = 3/(2i) = (3i) / (2i^2) = -3i/2 #
Let z = 5 + 12i, conj(z) = Z = 5-12i Expression becomes: [Sqrt(z) + Sqrt(Z)] / [Sqrt(z) - Sqrt(Z)] = [Sqrt(z) + Sqrt(Z)]^2 / [z - Z] = (z + Z + 2Sqrt(zZ)) / (z-Z) = (10 + 2Sqrt(169)) / (24i) = (10 + 26) / 24i = 36/(24i) = 3/(2i) = (3i) / (2i^2) = -3i/2 #
Trev stix Joined Jun 28, 2004 Messages 2,035 Location Pine Palace, St. Lucia, Brisbane. Gender Male HSC 2005 Oct 23, 2005 #3 [√(5+12i)+√(5-12i)]/[√(5+12i)-√(5-12i)] Rationalising the denominator: = [√(5+12i)+√(5-12i)]/[√(5+12i)-√(5-12i)] * [√(5+12i)+√(5-12i)]/[√(5+12i)+√(5-12i)] = [(5+12i)+2√(25-144i²)+(5-12i)]/[5+12i-5+12i] = [10+2.13]/[24i] = 36/[24i] =-3i/2 Hope there's not a mistake
[√(5+12i)+√(5-12i)]/[√(5+12i)-√(5-12i)] Rationalising the denominator: = [√(5+12i)+√(5-12i)]/[√(5+12i)-√(5-12i)] * [√(5+12i)+√(5-12i)]/[√(5+12i)+√(5-12i)] = [(5+12i)+2√(25-144i²)+(5-12i)]/[5+12i-5+12i] = [10+2.13]/[24i] = 36/[24i] =-3i/2 Hope there's not a mistake
I icycloud Guest Oct 23, 2005 #4 Trev said: Hope there's not a mistake Click to expand... Unless we both made the same mistake .