tutoring
hey, in one of ur posts u said ur in a critical need of a tutor for the subjects you mentioned. I think i am available to teach you maths 3/4 units. I would be unable to teach u 3Unit english, since i didnt do it, even though i could help u out a little bit with the 2unit english...
complex
umm...its a pretty interesting question ben, and some nice working out there by antwan2bu.
when i looked at this question the way i solved it was this way
given that (1+i)^n = x +iy prove that 2^n = x^2 +y^2
(1+i)^n = x + iy
multiply both sides by their conjugates so...
I tried this question but the answer in the back seems to be different, can someone help me out? thanks
The questions are:
1) If a conical pendulum is 1.4m long and the semivertex angle of the cone is 30 degrees find the period of rotation adn the tension in the string when the mass of the...
Guys i'd much appreciate if u cud help me in solving this volumes question, once agian the answer seems to be different to mine. Anyways, i'd give it to you guys
thanks. i've attached the diagram. The question is:
The area common to the circles x^2 + y^2 = 16 and x^2 + y^2 = 8x is revolved...
Guys, i'd much appreciate if u cud do this volumes question for me, ive attached the diagram for u and the question as follows:thanks
A solid has a cross sectional area given by A(h)= 36 + 21h - 2h^2 where h is the perpendicular distance above its base. If the height of the solid is 12 cm...
hey brett 86....thanx alot for ur detailed reply to my question on volume, thanx once again mate. Um i might need more help at a later date and ill be seeking ur advice on them too. Thanks once again
I tried this volumes questions a few time earlier, yet the answer at the back seems to be different to mine. Well i have attached the diagram and the question is the following: Plz help anyone, thanx!
The truncated cone in the diagram has end radii 6 cm and 12 cm. A horizontal slice, h cm...
answer to inverse function
the answer to that last question is
f(x) = x^2 + 2x
which means y= x^2 + 2x
Interchanging x with y,you get
x = y^2 + 2y.
and now make y the subject of the formula, using completing the squares
therefore,
x + 1 = y^2 + 2y +1
x + 1 = (y + 1)^2...
A particle of mass 4kg moves from rest under the action of a force whose magnitude after t seconds is 6-2t kg wt. When the particle reaches a speed of 19.6 m/s, the force ceases and the particle continues at constant speed for 5s, and is then brought to rest by a constant force of 5kg wt...