Any ring which is not an integral domain will have that property. Called zero devisors. for example consider the ring of integers modulo 4: 2*2 = 4 = 0 ; but 2 is not zero.
...it basically depends on the how you define your operations. For all I care you could define the multiplication to be...
looks correct to me. Assuming the smaller bowl is thin, the volume "ice bowl" can hold is the same as the volume of smaller bowl.
[of course in all of these we are assuming the top of the bowls used are in the same plane, else it has to be factored in]
x -> 1/2 (-1 - Sqrt[-3 + 4 Sqrt[11]]);
x -> 1/2 (-1 + Sqrt[-3 + 4 Sqrt[11]]);
x -> 1/2 (-1 - i Sqrt[3 + 4 Sqrt[11]]);
x -> 1/2 (-1 + i Sqrt[3 + 4 Sqrt[11]]).
...from the source of all wisdom: Mathematica
....here's how you do it by hand:
0 = x^4 + 2 x^3 + 3 x^2 + 2 x - 10
=...
although you mention that the question is not HSC type; but even a general maths student knows how to that question. Could probably bet a year 10 kid could do that question. All you need is a pencil that can last long enough to draw a few semi straight lines back and forth.
It doesn't belong...
Re: Semester I 2007 - Chatter Thread!
/begin{whining and winging}
Don't know how many of you people do Physics and Maths, 3rd year; but why the hell are there so many clashes between Maths and Physics. MATH3962, MATH3961 and MATH3974 all clash with Physics one way or another. Haven't checked...
Use implicit differentiation in the first one:
u^2 = 4-x^2 => 2u*du/dx = -2x =>-udu = xdx. then the Integral = Integral[(u^4-4u^2)du] integrated from 2 to 0. It gives 64/15.
damn why didn't I think of that. Thanks mate.
Then again, screw you fro not allowing me get a new PC so i could play Oblivion on :mad1:
...means more time for studies....thnx :)