Are the Cambridge Mathematics Extension 1 books more comprehensive in coverage than Fitzpatrick? I find that the Fitzpatrick Mathematics Extension 1 book leaves a lot of things out. What about the Cambridge Mathematics Extension 2 book? Why are the explanations sometimes not clear in it? Is it...
@Riviet: True, but the fact is that a normal does exist at the point t = 0, with its equation being x = 0 (i.e. the axis of the parabola). Therefore, I would say that it would be rightful to exclude t = 0 from the given coordinates of R, as the methods used to obtain R assume that t does not...
Sorry to bump this thread up, but there's one place of uncertainty regarding r3v3ng3's solution... In the section of his solution where he is finding the point R: when he is finding the y-coordinate of this point he substituted the x-coordinate which he found into one of the equations he began...
When you see a constant in an equation in physics, what does it mean and what is its purpose? This has always puzzled me... What about this whole deal with "using SI units", etc... What influence does a change of units have on constants in physics? I read in Wikipedia that certain units exist...
Thank you very much. Both of you have helped me. Stupid old me slightly misinterpreted the question, and also didn't know what to do in some respects. I especially like the way the locus was obtained in the end (by the elimination of s + t), I never would've thought to do it like that -- I was...
How do I solve this question on the parametric equation of the parabola from the Fitzpatrick Mathematics Extension 1 book:
24(c): 19. The normals to the parabola x^2 = 4ay at the point P(2at, at^2) and Q(2as, as^2) meet at R. Find the co-ordinates of R in terms of t and s. If st = -2, find the...
Ohm's law states: I = V / R . Jacaranda Preliminary HSC Physics states that measuring current on both sides of a resistor will give the same reading. But if you go by Ohm's law, increasing the variable R will decrease the value of the fraction V / R (k/x -> 0 as x -> infinity - basic maths)...
Around what mark is the UAI cutoff for HECS-HELP eligibility usually situated? 80.00? Higher? Is there even a general cutoff point? The two posters above seem to have contradicted each other slightly: so, are the places limited or not? The second poster implies that they aren't, and you are...
Ah okay, thanks for that. I am an Australian citizen, so I guess I do qualify.
Are the amount of government-supported places limited? Is there a difficulty involved in obtaining this loan? (Do you need to score marks over a certain threshold?)
Also, out of curiosity, what are these "union fees"?
Like everybody, I know about the HECS-HELP payment scheme. But I'm a little confused, I haven't quite comprehended completely or properly what people have been telling me or what I have read on the information website.
To put it bluntly (without going into further details about my stupidity in...