Search results

Hi everyone, I am currently offering Japanese tutoring for students who are studying Japanese Beginners/ Continuers/ Extension. Junior students who are studying Japanese or simply interested in starting Japanese are also welcomed. Profile: I have achieved band 6 in both Japanese...

Hi, I am currently offering Japanese tutoring for students who are studying Japanese Beginners/ Continuers/ Extension. Junior students who are studying Japanese or simply interested in starting Japanese are also welcomed. Profile: I have achieved band 6 in both Japanese Continuers...

I am doing B com/ arts (first year) and planning to major in Jap. I am not sure which one should I study for the other arts major though... sociology or philosophy? I read the handbook's description but still don't really know what to expect from these two courses... So can anyone give me an...

Does anyone have the answer for the 2005 HSC Trial Exam Paper?

For a particle moving along the x-axis, a=2x^3 - 10x. When x=4, v=(105)^1/2, show that x>3

1. a formula for the rate of change in population of a colony of bacteria is given by: P = 3200 + 400 e^kt. If the population double after 20hrs, how long it take to triple the original population. 2. In a certain bacteria culture, the rate of increase is proportioned to the number of...

To students who are doing Japanese Extension: what additional/ supporting text(s) do you use when doing language analysis? & a quick question... 湯婆婆：これから来るお客を、大湯で世話するんだよ。 Yubaba: korekara kuru okyaku wo, ooyu de sewa suru-n-da-yo. [extract 3 section 3] 'cause all our teacher said was...

Sorry I am having trouble in doing the last part of the question [prove true n=k+1] can anyone help please? 1) see attached img 2) 1+(1+x) + (1+x)^2 + ... + (1+x)^n = [(1+x)^(n+1) -1]/x 3) 1/(x^n)(x-1) = 1/(x-1) - 1/(x^2)(x-1) - ... - 1/(x^n)

Sorry, maybe i used wrong method or just did some silly mistakes... i just couldn't get the answer... =.="" Use Simpson's rule with five function values to estimate the volume of the solid formed by rotating the curve y=1/(1+x^2) about the x-axis b/w x= -2 & x=2. Answer: 34/25π Thanks in...

At any point on the curve y=f(x) the second derivative is given by f"(x)=2x-1. The tangent at the point (0,1) on the curve has gradient 1. Find the equation of the curve. Ans: y= (x^3)/3 - (x^2)/2 + x + 1 Thanks in advance.