Completed my HSC last year, but I wrote something like this in the exam. Directly from my notes: "Unknowingly, Shakespeare extends this textual conversation to Pacino who ironically adopts the role of Richard to a far greater extent than initially perceptible. Through the omission of physiognomy...
I dont remember circuits too well but i believe you minus the voltage drop from the first resistor. So V = 15 - 4 = 11V. Then you use this voltage for the second resistor and the current from part a.
For Usyd if you get the required atar and do well in the interview/assessment to get into the double degree Bachelor of science/Doctor of dental medicine, you wont have to do any other test (no ucat or gamsat).
The stopping voltage required to stop the electrons is provided by: KEmax=eV where V is the stopping voltage. Therefore for each frequency the voltage would be equal to the kinetic energy of the photoelectrons. For example at 6 x 10^14 Hz the KEmax would be 0.16eV.
Using KEmax = hf - work...
Due the larger difference in height from the starting point and the conservation of energy, the KE (and the velocity) will be higher at A (since change in GPE = change in KE). The radius is only for the arc of the circle at the troughs which I guess in this case is assumed to be the same, hence...
This is all i got, close to 40 trials. Might be some repeated files.
https://drive.google.com/drive/folders/1CetnXOpKQdJOnp7YBKYmhe3w5SOeK4SJ?usp=sharing
For Paper 1, short answer is there extra writing space because I haven't seen it. If not, are you able to write past the given lines. Would they still mark it as long as it's within the boxed margins?