If you get to (x^2+3x+4)/((x-2)^2(x-3)) = A/((x-2)^2) + B/(x-2) + C/(x-3), then you can say that (x^2 + 3x + 4) = A(x-3) + B(x-2) + C(x-2)^2.. then if you let x=2, the B and C terms will go to 0, allowing you to easily find A (14 = -A).. Once you have found A, you can expand the right hand side...
Simple differentiation and integration allows us to find acceleration, velocity and displacement in terms of time.. v = dx/dt and a = dv/dt.. By using this special result, we can find acceleration and velocity in terms of x(displacement)
I was lucky in that I was doing Yr 11 3U while i was in Yr 10, and so i learnt the 3U method for doing projectiles before learning the physics method.. I think that the 3U method is much safer (each question is done the same) and foolproof.. I also used the 3U method for physics projectiles...
Hey guys.. Just wondering what ATAR you think is achievable for me as im quite unsure of what to expect.
School rank ~ 150
2009 HSC
Maths Ext1. 1/13 - 92 E4
2010 Assessment
Maths Ext2. 1/3 - 81%
Physics 1/14 - 86%
Chemistry 2/18 - 90%
Economics 1/5 - 87%
Adv. English...
Hey guys.. Just wondering what ATAR you think is achievable for me as im quite nsure of what to expect.
School rank ~ 150
2009 HSC
Maths Ext1. 1st - 92 E4
2010 Assessment
Maths Ext2. 1st - 81%
Physics 1st - 86%
Chemistry 2nd - 90%
Economics 1st - 87%
Adv. English...