Recent content by roadrage75

you can create a triangle with sides: t, root(1-t^2) and hypotenuse 1 and then solve for t

Re: another question cool :)

Re: another question it's b^2 -4ac, not b^2 - 4bc

Re: another question why don't you?

Re: another question i don't think you calculated delta correctly.... i think delta = -3a^2 -6a + 1..... and now all you have to prove is that delta <0 for all positive integers 'a', and ther're many ways to do that!

this might sound really sily, but maybe read out the questions/statements in english first, so "How old are you?" "I'm 17" "I'll be 18 in 8 months", and then try to say them in french again....

yeah, the first few days can be a little rough, but once you have your tutorials and the like, you meet new people pretty quickly.... im in 3rd year now, and i know pretty much everyone in all my classes ;)

mais bien sur c'est difficile, voila ce a quoi on devrait s'attendre quand on fait une matiere comme cela! Quand je le faisais y a quelques annees, on a etudie un film, et c'etait difficile..... les questions que les profs en posaient etaient souvent tres philosophes et inattendues.... mais...

anyone here doing beginners italian!?!?! I don't reckon there'll be that many people doing it.... so just curious to see if anyone on bos is enrolled! ;)

voila! Bonne chance!

yep i am! beginners spannish

can you understand how I got to this step: (z-1)(z^2 +z + 1) = 0 now z = 1 satifies this equation, right? (this makes sense as 1 is one of the three cubic roots of 1) if z = 1, z^2 + z + 1 = 3 (by mere substitution) the only other way (z-1)(z^2 +z + 1) can = 0 is if z^2 + z...

:) thanks gizza! and bump!

i'd say so... notice there're not asking you to find out all the cube roots of unity. They're asking you to find the possible values for z^2 + z + 1, given that z is a cube root of unity as shuning said, z^3 = 1. therefore, (z-1)(z^2 + z + 1) = 0 so either z = 1 --> z^2 + z + 1...

i disagree. you can take up advanced maths subjects in 2nd year if you get a credit in NORMAL maths.... which suggests a pass in advanced maths and you should be alright.