Recent content by lilfrenchi

u forgot P1 _ _ _ _ P2 = 4! and P2 _ _ _ _ P1 = 4! which gives 6*4!/6! which is the same as 3!*4!/6!

for that 1 i just let u=x^4 du/dx = 4x^3 d(tan^-1 u)/du = 1/1+u^2 du/dx * d(tan^-1 x^4)/du = 4x^3/1+(x^4)^2

i counted the 4 children as one since they are seatin together then multiplied it by the way they can be arranged together. then divided that by 6! therefore 3!*4!/6! duno if im right tho

YES THATS WAT I GOT TOOOOOO!!! =]

add the 2 equations to get arcsinx + 3arcsinx = pi/3 + 2pi/3 4arcsinx=pi arcsinx= pi/4 x=1/sqrt2 then sub that in one of the equations to find y

I(0-->10)50-50e^(-0.2t) = [50t +250e^(-0.2t)]0-->10 cant find my calculator lol sorry

did anyone do q7 (ii)? thats the only q i couldnt do lol

u dnt need to find C since you're using limits

integrate v with limits 0-->10 i think?

That Was So Easy !!!!!!!!!!!!! Im So Happy First Exam I Actually Think I Aced

HOW DID U GET IT SO FAST LOL!!!!!!!!! i get really close to 1 lol but cant get there please post the solutions lol this is kilin me

i think for 2) |z|=1 im not really sure tho

how do u do that??

would u lose marks if u talked about the same radioisotope for both medical and industry? i only studied cobalt-60 for both medical and industry, i knew a question like that would come up but i thought it woulda said medicine OR industry. i talked about cancer treatment for medicine and...

wrote 3 pages of stuff that didnt make any sense. hardest question in the exam for me. what were you suppose to talk about. did you guys do Bruce Dawe?