Hi everyone. For trig i got this question:
y=cosx-sinx graph this equation.
I know of one way to graph it thanks to pluvia. But how do we graph it using the auxiliary method in other words how do we graph y=sqrt{2}cos(x-pi/4)
Thanks for ur help. ;)
Thanks heaps but i dont understand the auxiliary method. How to get sqrt 2 and how to graph it. If you could explain it to me please, thanks a million. ;)
Sutton worked with grasshoppers because of their chromosomes. He concluded that chromosomes were responsible for inheritance and that mendel's factors (genes) were located on chromosomes. He also concluded that different factors appear on different chromosomes.
Boveri worked with sea urchins...
Hi everyone. Hope everyones doin gud and studyin hard. I jus got a question on calculus.
"Although the amount of pollution is increasing, The Government's policies to reduce pollution seems to be taking effect."
Given that P is the amount of pollution, what does the above statement imply...
Sweet thanks. Okay jus a stupid question. For sin (theta - alfa) = 1/rt2
it equlas pi/4, 3pie/4, 9pi/4, 11pi/4,.......
Um how do we actually come to these results. I thought it was jus the first two but i cudnt get the rest. :(
Hey im back. I got another question. I HATE TRIG.
Okay.
Find all the angles x with 0 < or equal x < or equal to 2pie for which sinx + cosx = 1
Once again thank you for helping me.
Sweet. I get it. Thanks heaps. I appreciate it.
Im not very good at 3 unit so i'll definitely ask more questions. lol. But i'll always try.
Thanks everyone, good luc studyin and hope u could help me l8r.
Hi everyone. Hope ur all goin gud. Not long for the HSC.
Well i got this question for trig. show that if 0 < x<pie on four
then cos2x>2sin squared x minus one?
I cant write maths things here. thanks heaps if u cud help me.
Hi everyone. Hope ur all goin gud. Not long for the HSC.
Well i got this question for trig. show that if 0 < x < pie on four
then cos2x>2sin squared x minus one?
I cant write maths things here. thanks heaps if u cud help me.