Recent content by chaosflaws

You're perfectly right, I forgot the square in my head. Will write it down next time ;)

1. Sketch. Break the integral up at the intersection of the two curves, then take two separate integrals. Solution: \frac{1}{2}+\ln{2} 2. Remember to square the function (it does not look so terrible any more then) and to multiply by Pi. Solution: \pi \ln{3} 3. Note that you are not going around...

dunlop, first of all: don't worry. You've got 12 units. Even if Ancient pulls you down more than can reasonably expected, it will probably not count for your ATAR if you carry on everything else. And, as brent said, choose what you like to do. Scaling is not there to disadvantage some subjects...

Quotient rule is the straightforward way. Transforming it into a product and then doing product rule gives you exactly your quotient rule formula anyway: y = f(x) * (g(x))^(-1) dy/dx = f'(x) * (g(x))^(-1) + f(x) * g'(x) * (-1) * (g(x))^(-2) dy/dx = f'(x) / g(x) - f(x) * g'(x) / (g(x))^2...

Exactly the same problem here.