I think the highest aggregate ever was achieved by this guy called Vincent at Ruse. You should see his rankings:
1st in state for chem=100
1st in state for phys=100
3rd in state for bio=98
and some other absurd ranking for 4u maths and eng.
100UAI in the endxD
erm, in fitzpatrick 3unit, within the simple harmonic motion section, they always refer to the mean position. I am currently misunderstanding whether the mean position means:
t=0(time equals 0)
displacement=0
or whenever the harmonic motion graph crosses the x-axis(that is, the 'roots')
Thanks :)
hmm
for the 1st ten numbers: S=a(r^10 -1)/(r-1)=4
for the 1st 30 numbers: S= a(r^30 -1)/(r-1)=48+4=52
so i divided them and got: (r^30-1)/(r^10-1)=13
now im stuck again xD
Edit: Ive got it solved:
Sum between 31-60= Sum60-Sum30
and work it out from there :)
The final answer i got was...
Hey guys, i was wondering if you could help me out on this Q:
Given a geometric sequence whose sum of the first 10 terms is 4 and whose sum from the 11th to the 30th term is 48, find the sum from the 31st to the 60th term.
Im kinda stuck at the moment :S
me doing 4unit maths and 4unit eng at JRAHS. I think at least 10 ppl are in the same boat as me.
we have 90something students doing 4u maths and 60something for 4u eng
Hooray for four morning classes in the morning xD