Probably same as yours..
1. we know that resisitance r = kv^2, use inforamtion form the first part to work out k:
Total Force in the cirection down the slope: F = gm/30 - kv^2
In particular, F = 0 when v = 30, gives k = gm/27000
The seconf part asks you to find the additional Force F up the...
if e = p/q then (e-s_q)*q! = (q-1)!*p - q! * s_n
which is an integer (q! * s_n ----> Check term by term)
Which contradicts (c), so you can't have e = p/q for some p,q
But that is almost never true given that all but at most 1 of the a's need to be less than 1.
Need to be less generous with the other part to prove the whole inequality.
in case someone's not too familiar with the terms:
semiperimeter --> 1/2 the perimeter
inradius ---> the radius of the circle with the 2 edges as tangents
circumradius --> radius of the circle passing through the 3 corners
heights -> perpendicular distance from a corner to the opposite edge
let T = (x,y) then
(x-cp) + p^2 (y - c/p) = 0
x + (p^2)y = 2cp
x + (q^2)y = 2cq
x = 2c / (p+q)
y = 2cpq/(p+q) = 2c / (p+q) = 2c / (p + 1/p)
so the line's x=y , x in [-c,c]
as p + 1/p >= 2 or p + 1/p <= -2
EDIT: thought about it again
if we allow p = q then it's the above line segment + 2...
what "you" here refers to:
University
Marks
Any other Qualifications
Intern experience
Extracurriculars
Your impression at the interview.
So marks are still a major factor here as it is probably the best availalble measure of performance in your most recent main occupation. But the...